4-16d^2=0

Solution for 4-16d^2=0 equation:

4-16d^2=0

a = -16; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-16)·4
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*-16}=\frac{-16}{-32}
=1/2
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*-16}=\frac{16}{-32}
=-1/2
$